LC address: https://leetcode.com/problems/missing-number/
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
For example,
Given nums = [0, 1, 3]
return 2
.
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
Analysis:
换汤不换药的题目,XOR就能解决。
Solution:
public class Solution { public int missingNumber(int[] nums) { int result = nums.length; for (int i = 0; i < nums.length; i++) { result = result ^ i ^nums[i]; } return result; } }
Solution code can also be found here: https://github.com/all4win/LeetCode.git
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